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In a fcc arrangement of A and B atoms, atoms A are at the corners of the unit cell and B atoms are at the face center. One of the A atom is missing from one corner of unit cell. The simplest formula of the compound is

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a

A7B3

b

AB3

c

A7B24

d

A78B6

answer is C.

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Detailed Solution

Effective number of atoms of at the corners =7×18 Effective atoms of B at face centres of unit cell =6×12 Thus A :B =78 :3 or 7: 24

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