In a FCC arrangement of A and B atoms, atoms ‘A’ occupy the corners of the unit cell and ‘B’ atoms occupy the face centers. One of the ‘A’ atom is missing from one corner of unit cell. The simplest formula of the compound is
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a
A7B3
b
AB4
c
A7B24
d
A78B6
answer is C.
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Detailed Solution
There are total 8 corners and each contributes one eighth to the unit cell One of the A atom is missing from one corner in unit cell Thus Effective number of A atoms of at the corners =7×18 B atoms are at the face centres. There are 6 face centres Thus Effective atoms of B at face centres of unit cell =6×12 Thus A :B =78 :3 or 7: 24Formula of the compound is A7B24