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Q.

Fe2O3(s) may be converted to Fe by the reaction  Fe2O3(s)+3H2(g)⇌2Fe(s)+3H2O(g) for which Kc = 8 at temp. 720oC What percentage of the H2 remains unreacted after the reaction has come to equilibrium?

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a

≃22%

b

≃34%

c

≃66%

d

=78%

answer is B.

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Detailed Solution

Let initial moles of H2(g) is 1          Fe2O3(s)+3H2(g)⇌2Fe(s)+3H2O(g) at eq.;               1-3x                   3x Kc=3xV31-3xV3 ⇒ 8=3x1-3x3 x =0.22 % of H2 unreacted  =1-3×0.221×100=34
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