Fe(excess) + Cl2→Product XFe + Cl2 (excess) →Product Y , X and Y are respectively
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
FeCl2 ;FeCl3
b
FeCl3 ;FeCl2
c
FeCl2 in both reactions
d
FeCl3 in both reactions
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Whenever a reaction between an oxidizing agent and a reducing agent is carried out :If reducing agent is in excess compound of lower oxidation state is formed X = FeCl2 ( iron is reducing agent in excess)If oxidizing agent is in excess compound of higher oxidation state is formed Y = FeCl3 (Chlorine is oxidizing agent in excess)