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The final product of the given reaction is?
$HC \equiv CH \to_{Et - I excess}^{Excess {NaNH}_{2}}$

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Correct option is C

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The final product of the given reaction is? HC≡CH→Et-I excessExcess NaNH2

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Ready to Test Your Skills?

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The final product of the given reaction is?
$HC \equiv CH \to_{Et - I excess}^{Excess {NaNH}_{2}}$