Find the correct answer based on the number of minimum carbons required for alkyne to show the corresponding isomerism
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a
(i)–(a); (ii)–(b); (iii)–(c); (iv)–(d); (v)–(e)
b
(i)–(d); (ii)–(c); (iii)–(b); (iv)–(b); (v)–(e)
c
(i)–(d); (ii)–(c); (iii)–(b); (iv)–(a); (v)–(e)
d
(i)–(d); (ii)–(c); (iii)–(a); (iv)–(b); (v)–(e)
answer is B.
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Detailed Solution
Alkynes must have minimum 5 carbons to show chain isomerism, 4 carbons to show positional isomerism, 3 carbons to show functional isomerism, 3 carbons to show Ring chain isomerism, and 6 carbons to show Optical isomerism