Find the equivalent weight of Ca(OH)2 in the following reaction.Ca(OH)2+2H2SO4⟶CaHSO42+2H2O (at. wt., Ca=40,O=16,H=1 )

First method.Mol. wt. of Ca(OH)2=40+2(16+1)=74gmol−Reaction.Ca(OH)2+2H2SO4⟼CaHSO42+2H2O1 molecule                               no OH-group= 2 OH-groups.∴  No. of OH-groups replaced from one molecule ofCa(OH)2=2−0=2.∴ Eq. wt. of Ca(OH)2= Mol. wt. of Ca(OH)2 no. of OH-groups replaced  from one molecule of Ca(OH)2                                     =742=37 Ans.Second methodCa(OH)2  + 2H2SO4 ⟶ CaHSO42 + 2H2O1 molecule     =2×2H+ions             =2×1H+ions                       =4H+ion                        =2H+ion ∴   No. of H+ions that react with one molecule of  Ca(OH)2=4-2=2.∴  Eq. wt. of Ca(OH)2= Mol. wt. of Ca(OH)2 No. of H+ions that react  with one molecule of Ca(OH)2                                              =742=37 Ans.