Find the equivalent weight of Ca(OH)2 in the following reaction.Ca(OH)2+2H2SO4⟶CaHSO42+2H2O (at. wt., Ca=40,O=16,H=1 )

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answer is 37.

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Detailed Solution

First method.Mol. wt. of Ca(OH)2=40+2(16+1)=74gmol−Reaction.Ca(OH)2+2H2SO4⟼CaHSO42+2H2O1 molecule no OH-group= 2 OH-groups.∴ No. of OH-groups replaced from one molecule ofCa(OH)2=2−0=2.∴ Eq. wt. of Ca(OH)2= Mol. wt. of Ca(OH)2 no. of OH-groups replaced from one molecule of Ca(OH)2 =742=37 Ans.Second methodCa(OH)2 + 2H2SO4 ⟶ CaHSO42 + 2H2O1 molecule =2×2H+ions =2×1H+ions =4H+ion =2H+ion ∴ No. of H+ions that react with one molecule of Ca(OH)2=4-2=2.∴ Eq. wt. of Ca(OH)2= Mol. wt. of Ca(OH)2 No. of H+ions that react with one molecule of Ca(OH)2 =742=37 Ans.

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