Find the incorrect equation among the following.

Applying gibbs energy, ΔG=ΔH−TΔSWhere, ΔG  is the change in gibbs energyΔH is the change in enthalpyΔS is the change in entropyT is temperaturea) For a system, total entropy change =ΔStotal ΔHtotal =0∴ΔGsystem =−TΔStotal ∴ΔGsystem ΔStotal =−TThus (a) is correct b) For isothermal reversible process,  ΔE=0By first law of thermodynamics,  ΔE=q+W∴Wreversible =−q=−∫ViVf pdV⇒Wreversible =−nRTln⁡VfVi Thus, (b) is correct.c)  ΔG∘=ΔH∘−TΔS∘Also,  ΔG∘=−RTlnK⇒ln⁡K=−ΔG∘RT⇒ln⁡K=ΔH∘−TΔS∘RT[ from Equation (1)] Thus (c) is incorrect.d) The standard free energy  ΔG∘ is released to equilibrium constant  K as ΔG∘=−RTln⁡K∴ln⁡K=ΔG∘RT⇒K=−e−ΔG∘RTThus, (d) is also correct.