Find out in which option the order of reducing power is correct?

$$\begin{gathered} {\mathrm{E}}_{{\mathrm{Cr}}_2{\mathrm{O}}_7^{-2}|{\mathrm{Cr}}^{+3}}^{\circ } = 1.33 \mathrm{V} ; {\mathrm{E}}_{{\mathrm{Cl}}_2|\mathrm{Cl}}^{\circ } = 1.36 \mathrm{V} \\ {\mathrm{E}}_{{\mathrm{MnO}}_4^{-}|{\mathrm{Mn}}^{+2}}^{\circ } = 1.51 \mathrm{V} ; {\mathrm{E}}_{{\mathrm{Cr}}^{+3}|\mathrm{Cr}}^{\circ } = -0.74 \mathrm{V} \end{gathered}$$

• A

  ${\mathrm{Cr}}^{3+}<{\mathrm{Cl}}^{-}<{\mathrm{Mn}}^{2+}<\mathrm{Cr}$

• B

  ${\mathrm{Mn}}^{2+}<{\mathrm{Cl}}^{-}<{\mathrm{Cr}}^{3+}<\mathrm{Cr}$

• C

  ${\mathrm{Cr}}^{3+}<{\mathrm{Cl}}^{-}<{\mathrm{Cr}}_2{\mathrm{O}}_7^{2-}<{\mathrm{MnO}}_4^{-}$

• D

  ${\mathrm{Mn}}^{2+}<{\mathrm{Cr}}^{3+}<{\mathrm{Cl}}^{-}<\mathrm{Cr}$