Find the oxidation number of Cr in the complex CrNH33H2O3Cl3 and write its IUPAC name.

CrNH33H2O3Cl3O.N. of Cr +3 X O.N. of NH3+3 x O.N. of H2O+3×O.N of CI-= 0O.N. of Cr + (3 x 0) + (3 x 0) + (3 x -1) = 0;O.N. of Cr = + 3 - 0 - 0 = +3IUP AC name is, tri ammine tri aqua chromium (III) chloride