Q.
Find the pH of solution prepared by mixing 25 ml of a 0.5 M solution of HCl, 10 ml of a 0.5 M solution of NaOH and 15 ml of water
see full answer
Want to Fund your own JEE / NEET / Foundation preparation ??
Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya
a
0.8239
b
1.0029
c
1.0239
d
1.8239
answer is A.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
We know that HCl and NaOH reaction is neutralization,( m.e. = milli-equivalent)∴ m.e. of HCl = 0.5 × 25=12.5 m.e. of NaOH = 0.5 × 10=5.0m.e. of HCl in the resultant mixture= 12.5 - 5.0 = 7.5Total volume = (25 + 10 + 15) ml = 50 ml∴ Normality of HCl = m.e.Vol(ml)=7.5050 ∴ Molarity = 7.5050 ∴ H+ = 7.5050 ∴ pH = -log 7.5050 = 0.8239
Watch 3-min video & get full concept clarity