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Find the ratio of equivalent weight of MnO4- in acidic and basic media.

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answer is 0.6.

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Detailed Solution

MnO4-+8H++5e-→Mn2++4H2O (Acidic medium)MnO4-+2H2O+3e-→MnO2+4OH (Besic medium)If M is mol. wt. of KMnO4,then its Eq. wt. in acidic, basic are M5:M3 or 3:5=0.6

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