Q.
Find the value of mole fraction of the solute when vapour pressure of glucose is 750 mm Hg at 373 K in dilute solution.
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a
1/7.6
b
1/76
c
1/35
d
1/10
answer is B.
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Detailed Solution
P∘−PsP∘=nn+N∴ nn+N=760−750760=176n = number of moles of glucose N = number of moles of waterAt boiling point of water P0 = 1 atm = 760 mm Hg
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