Find the value of mole fraction of the solute when vapour pressure of glucose is 750 mm Hg at 373 K in dilute solution.

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1/7.6

1/76

1/35

1/10

answer is B.

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Detailed Solution

P∘−PsP∘=nn+N∴ nn+N=760−750760=176n = number of moles of glucose N = number of moles of waterAt boiling point of water P0 = 1 atm = 760 mm Hg

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