Q.
First ionisation enthalpy of an element is 756 kJ/mole. The change in enthalpy for the process Mg → M2+(g) will be
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a
900 kJ
b
2196 kJ
c
1071 kJ
d
1512 kJ
answer is B.
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Detailed Solution
GivenI.P1 of ‘M’ = + 756 kJ/mole ;I.P2 of ‘M’ must be > 756 kJ/mole ;Thus sum of I.P1 and I.P2 will be > 1512 kJThusMg →M2+g, ∆H >1512 kJ ;By inspection, the only option which is greater than 1512 kJ is Option (2) ;
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