First ionisation enthalpy of Magnesium is 738 kJ/mole. The change in enthalpy for the process Mgg → Mg2+(g) will be
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a
900 kJ
b
2188 kJ
c
1071 kJ
d
1475 kJ
answer is B.
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Detailed Solution
GivenI.P1 of Mg = + 738 kJ/mole ;I.P2 of Mg must be > 738 kJ/mole ;Thus sum of I.P1 and I.P2 will be > 1476 kJThusMgg →Mg2+g, ∆H >1476 kJ ;By inspection, the only option which is greater than 1476 kJ is Option (2)