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The first ionisation potential of Na is 5.1 eV. The value of electron gain enthalpy of Na+ will be

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a

−2.55 eV

b

−5.1 eV

c

−10.2 eV

d

+2.55 eV

answer is B.

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Detailed Solution

Na→ Na+ + e− First IENa++e−→ Electron gain enthalpy of Na+The reaction is reversed soΔHeg = −5.1 eV

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