The first IP of lithium is 5.41eV and electron affinity of Cl is -3.61eV. Calculate ΔH in KJmol–1 for the reaction Li(g) + Cl(g) → Li(g)+ + Cl–(g)

IP1 of Li is 5.41ev and EA of Cl is 3.6 evLi(g) → Li+(g) ΔH=+5.41evCl(g) → Cl-(g) ΔH=-3.6evΔH = 1.8(96.45)     = +173.7 KJLi(g) + Cl(g)  → Li+(g) + Cl-(g)  ΔH=+1.8ev