Q.
For the first order reaction A(g)→2B(g)+C(g), the initial pressure is PA=90 mm Hg, the pressure after 10 minutes is found to be 180 mm Hg. The rate constant of the reaction is
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a
1.15×10−3 sec−1
b
2.3×10−3 sec−1
c
3.45×10−3 sec−1
d
6×10−3 sec−1
answer is A.
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Detailed Solution
The reaction is A(g)→2B(g)+C(g)at t = 0 pressure PA 0 0Pressure after 10 mints PA−x 2x x Total pressure after 10 minutes, PT=PA+PB+PC PT=(PA−x)+2x+x=PA+2x=180∵ PA=90 mm90+2x=180 or, X=45mm∴ PA−x=90−45=45 mmSince, kt=2.303logPAPA−x k×10=2.303log9090−45k×10=0.693 k=0.69310=0.0693 min−1 =0.69310×60 sec=1.155×10−3sec−1
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