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Q.

For a first order reaction A→P the temperature (T) dependence of rate constant ‘k’ was found to follow the equation log10 K=6−2000T . The pre-exponential factor ’A’ and activation energy (Ea) respectively are

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a

1×106S−1and 9.2 KJ mol−1

b

6.0 S−1and 16.6 KJ mol−1

c

1×106 S−1and 16.6 KJ mol−1

d

1×106 S−1and 38.3 KJ mol−1

answer is D.

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Detailed Solution

We, know, log10K=log10A−Ea2.303 R×1T    −−−→(1) the given equation is log10K=6−2000T   −−−→(2) From equation (1) and (2) log10⁡A=6 ∴A=106S−1 (For firstorder   Ea2.303R=2000 Ea=2000×2.303×8.314 = 38294  J mole−1 =38.3   KJ  mole−1
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