For a first order reaction temperature coefficient is 2. If the value of K at 310K is 2×10-2 min-1, t12 of reaction at 300K will be

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Detailed Solution

Since temperature is decreased by 10° rate is halved ,also rate constant is halved. At 300°K ;rate constant k1=2×10-22=10-2 t12=0.69310-2=69.3 min

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