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Q.

For a first order reaction when log(a – x) on y-axis is plotted against time on x-axis. Slope of the graph will be equal to('a' is the initial concentration of the reactant and ‘x’ is concentration of reactant consumed in time ‘t’ )

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a

−K2.303

b

0.69310

c

K

d

2.303K

answer is A.

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Detailed Solution

K=2.303t  log  aa−x loga−loga−x=K2.303  ×t loga−x=loga−K2.303  ×t loga−xy=logac−K2.303m  ×tx Slope  = - K2.303
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