A flask contains a mixture of compounds A and B. Both compounds decompose by first-order kinetics. The half-lives for A and B are 300s and 180s, respectively. If the concentrations of A and B are equal initially, the time required for the concentration of A to be four times that of B (in s) is. (Use In 2 = 0.693)

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180

300

900

120

answer is C.

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Detailed Solution

Ak=A0⋅e−k1t4x=A0⋅e−k1t A0=B0x=80⋅e−k2t4=e−kt+k2tln⁡4=k2−k1tt=ln⁡yk2−k1=2×0.6830.6931180−1300=2×180−300300−180=2×100×100120 =900