Q.
In the following compounds(i) P4O10 (ii) Solid PI5calculate the value of X+Y6If X is the total number of sp3 hybridised atoms in both above compounds Y is the total number of sp2 hybridised atoms in both above compounds.
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya
answer is 2.5.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Structure of P4O10.All four 'P' atoms are sp3 hybridised six 'O' atoms are sp3 hydridised.Four 'O' atoms are sp2 hybridised.Total sp3 hybridised atoms in P4O10 = 4 + 6 = 10Total sp2 hybridised atoms in P4O10 = 4. (ii) Solid PI, exists as, PI4⊕sp3hybridizedI⊝Total number of sp3 hybridised atoms in PI5 = oneTotal number of sp2 hybridised atoms in PI5 = zero∴X=10+1=11Y=4+0=4(X+Y)6=156=2.5
Watch 3-min video & get full concept clarity