Following data is given at T $$=$$ $$298$$ K λ∘ eq for $$Ba(OH)2=228.8ohm$$−$$1cm2eq$$−$$1$$λ∘ eq for BaCℓ$$2=120.3ohm$$−$$1cm2eq$$−$$1$$λ$$0$$ eq for $$NH4C$$ℓ$$=129.8ohm$$−$$1cm2eq$$−$$1Specific$$ conductance for $$0.2N$$ $$NH4OH$$ solution $$is4.766$$×$$10$$–$$4ohm$$–$$1cm$$–$$1Then$$ the value of pH of the given solution of $$NH4OH$$ will be nearly.

Question

Following data is given at  T $$=$$ $$298$$ K λ∘ eq for $$Ba(OH)2=228.8ohm$$−$$1cm2eq$$−$$1$$λ∘ eq for BaCℓ$$2=120.3ohm$$−$$1cm2eq$$−$$1$$λ$$0$$ eq for $$NH4C$$ℓ$$=129.8ohm$$−$$1cm2eq$$−$$1Specific$$ conductance for $$0.2N$$    $$NH4OH$$ solution $$is4.766$$×$$10$$–$$4ohm$$–$$1cm$$–$$1Then$$ the value of pH of the given solution of $$NH4OH$$ will be nearly.

Infinity Learn · Accepted Answer

λ$$Ba(OH)2$$∘$$=$$λ$$Ba+2$$∘$$+$$λOH−∘λ$$BaCl2$$∘$$=$$λ$$Ba+2$$∘$$+$$λCl−∘λ$$NH4Cl$$∘$$=$$λ$$NH4$$∘$$+$$λCl−∘⇒λ$$NH4OH$$∘$$=$$λ$$NH4$$∘$$+$$λOH−∘$$=129.8+222.8$$−$$120.3=238.3$$∧m∘λ$$=K$$×$$1000C=4.766$$×$$10$$−$$4$$×$$10000.2$$⇒α$$=$$∧∧∘$$=0.01$$⇒OH−$$=0.01$$×$$0.2=2$$×$$10$$−$$3$$⇒POH−$$3$$−log⁡$$2pH$$ $$=$$ $$11.3$$

Detailed Solution

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