For the following electrochemical cell at 298K,Pt(s)   H2(g,1bar)H+(aq,1M)   M4+(aq),M2+(aq)   Pt(s)Ecell=0.092V when   M2+(aq)M4+(aq) =10xGiven:  EM4+/M2+0=0.151 V;2.303 RTF=0.059 V  The value of  x  is

Pt,H21 barH+1MM+4M+2Pt H2→2H++2e−,   E0=0 M+4+2e−→M+2,   E0=0.151 H2+M+4aqu→2H++M+2aqu;  E0=0.151 E=E0−2.303RTFlogH+2M+2M+4 ⇒0.092=0.151−2.303RT2FlogM+2aquM+4aqu⇒0.059=2.303RT2FlogM+2M+4 ⇒0.059=0.0592FlogM+2M+4⇒M+2M+4=102=10x⇒x=2