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Q.

The following equilibrium constants are givenN2 + 3H2 ⇌  2NH3;   K1N2 + O2 ⇌  2NO;   K2H2 + 12O2 ⇌  H2O;   K3The equilibrium constant of the reaction2NH3 + 52O2 ⇌ 2NO + 3H2O  in terms of K1, K2 and K3 is

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a

K=K2 × K32K1

b

K=K22 × K3K1

c

K=K1  × K2K3

d

K=K2 × K33K1

answer is D.

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Detailed Solution

For equilibrium,(a)  N2(g) + 3H2(g) ⇌  2NH3(g) K1=NH32N2 H23                                 ……(i)(b)   N2(g) + O2(g) ⇌  2NO(g)K2=NO2N2 O2                                   ……(ii)(c)  H2(g) + 12O2(g) ⇌  H2O(g)K3=H2OH2 O21/2                             …….(iii)For reaction,2NH3(g) + 52O2(g) ⇌  2NO(g) + 3H2O(g)  …….(iv)For getting K, we must doK33=H2O3H23 O23/2                                          ……(v)From eqs. (i) (ii) and (v)K=K2 × K33K1
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