The following equilibrium constants are givenN2 + 3H2 ⇌ 2NH3; K1N2 + O2 ⇌ 2NO; K2H2 + 12O2 ⇌ H2O; K3The equilibrium constant of the reaction2NH3 + 52O2 ⇌ 2NO + 3H2O in terms of K1, K2 and K3 is
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a
K=K2 × K32K1
b
K=K22 × K3K1
c
K=K1 × K2K3
d
K=K2 × K33K1
answer is D.
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Detailed Solution
For equilibrium,(a) N2(g) + 3H2(g) ⇌ 2NH3(g) K1=NH32N2 H23 ……(i)(b) N2(g) + O2(g) ⇌ 2NO(g)K2=NO2N2 O2 ……(ii)(c) H2(g) + 12O2(g) ⇌ H2O(g)K3=H2OH2 O21/2 …….(iii)For reaction,2NH3(g) + 52O2(g) ⇌ 2NO(g) + 3H2O(g) …….(iv)For getting K, we must doK33=H2O3H23 O23/2 ……(v)From eqs. (i) (ii) and (v)K=K2 × K33K1