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Following limiting molar conductivities are given asλm∘H2SO4=x Scm2mol−1 λm∘K2SO4=y Scm2mol−1 λm∘CH3COOK=z Scm2mol−1 λm∘ (in Scm2mol−1 ) for CH3COOH willbe

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Detailed Solution

According to Kohlrausch's lawλmo(AB)=λmoA++λmoB− So, λmoCH3COOH=λm∘CH3COO−+λmoH+ So λmoCH3COOH=λmoCH3COOK+12λmoH2SO4−12λm∘K2SO4=z+x2−y2=z+x−y2
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