Of the following 0.10 m aqueous solutions, which one will exhibit the largest freezing point depression?
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a
KCl
b
C6H12O6
c
Al2(SO4)3
d
K2SO4
answer is C.
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Detailed Solution
Freezing point depression (∆Tf) is a colligative property and depends upon the van't Hoff factor (i), i.e. number of ions given by the electrolyte in aqueous solution. ∆Tf=i×Kf×mWhere, Kf=molal freezing point depression constant m= molality of the solution∴Kf and m are constant ∴∆Tf∝i(a) KCl(aq)⇌K+(aq)+Cl-(aq)(total ions =2 thus,i=2)(b) C2H12O6⇌no ions [i=0](c ) Al2SO43(aq)⇌2Al3++3SO42- (total ions -5, thus, i = 5)(d)K2SO4(aq)⇌2K++SO42-(total ions - 3,thus, i = 3)Hence, Al2(SO4)3 will exhibit largest freezing point depression due to the highest value of i.