Q.

For the following molecules:PCl5,BrF3,ICl2-,XeF5-,NO3-,XeO2 F2,PCl4+,CH3+Calculate the value of a+bca = Number of species having sp3d -hybridizationb = Number of species which are planar c = Number of species which are non-planar

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answer is 3.

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Detailed Solution

PCl5⟶sp3d, non-planar BrF3⟶sp3d, bent, T-shape, planar ICl2-⟶sp3d, linear, planar XeF5-⟶sp3d3, pentagonal planar NO3-⟶sp2, planar XeO2 F2⟶sp3d, see-saw, non-planar PCl4+⟶sp3, tetrahedral, non-planar CH3+⟶sp2, Trigonal planar a=4, b=5, c=3  so, a+bc=3
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For the following molecules:PCl5,BrF3,ICl2-,XeF5-,NO3-,XeO2 F2,PCl4+,CH3+Calculate the value of a+bca = Number of species having sp3d -hybridizationb = Number of species which are planar c = Number of species which are non-planar