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An Intiative by Sri Chaitanya
a
CH2 = CH –CH2Cl > CH3CH2CH2Cl > CH3CH =CHCl
b
CH2 = CH –CH2Cl > CH3CH2CH2Cl < CH3CH =CHCl
c
CH2 = CH –CH2Cl < CH3CH2CH2Cl > CH3CH =CHCl
d
CH2 = CH –CH2Cl < CH3CH2CH2Cl < CH3CH =CHCl
answer is A.
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