In the following process of disproportionation,2ClO3−Chlorate ion⇌ClO2−+ClO4−Perchlorate ion;EClO4−/ClO3−o=+0.36VEClO3−/ClO2−o=+0.33VInitial concentration of chlorate ion was 0.1 M. The equilibrium concentration of per chlorate ion will be 1.9×10−x. Hence x is

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Detailed Solution

ClO3−aq+H2Ol→ClO4−aq+2H+aq+2e−2H++ClO3−aq+2e−→ClO2−aq+H2Ol2ClO3−aq⇌ClO2−aq+ClO4−aqEcello=0.33−0.36=−0.03VE=Eo−0.059nlogQAt equilibrium, E=0, n=2, Q=K0=−0.03−0.0592logKlogK=−1K=110K=x×x0.1−2x2=110x=0.019

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