In following reaction $$3A(g)+B(g)$$⇌$$2X(g)+Y(g)$$ if initial concentration of B is double that of A and at equilibrium concentrations of A & X are equal the percentage B of reacted to attain equilibrium is

Question

In following reaction $$3A(g)+B(g)$$⇌$$2X(g)+Y(g)$$ if initial concentration of B is double that of A  and at equilibrium concentrations of A & X are equal the percentage B of reacted to attain equilibrium is

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[B]initial $$=2$$[A]initid                                            $$3A$$   $$+$$   B   ⇌   $$2X+Y$$ Initial concentration              c           $$2c$$          $$0$$      $$0$$                                         $$-3c$$α    $$-c$$α  $$+$$  $$2c$$α $$+c$$α Final concentration           $$c-3c$$α  $$2c-c$$α  $$2c$$α  cα ∵[A]equilibrium $$=$$[X]equilibrium  $$c-3c$$α$$=2c$$α$$5c$$α$$=c$$α$$=0.2$$ % of B reacted  $$=0.2c2c$$×$$100$$ $$=10.00$$

In following reaction 3A(g)+B(g)⇌2X(g)+Y(g) if initial concentration of B is double that of A and at equilibrium concentrations of A & X are equal the percentage B of reacted to attain equilibrium is

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