Q.
In following reaction 3A(g)+B(g)⇌2X(g)+Y(g) if initial concentration of B is double that of A and at equilibrium concentrations of A & X are equal the percentage B of reacted to attain equilibrium is
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answer is 10.00.
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Detailed Solution
[B]initial =2[A]initid 3A + B ⇌ 2X+Y Initial concentration c 2c 0 0 -3cα -cα + 2cα +cα Final concentration c-3cα 2c-cα 2cα cα ∵[A]equilibrium =[X]equilibrium c-3cα=2cα5cα=cα=0.2 % of B reacted =0.2c2c×100 =10.00
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