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Q.

For the following reaction, the mass of water produced from 445g of C57H110O6 is2C57H110O6(s)+163O2(g)→114CO2(g)+110H2O(l)

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a

495 g

b

490 g

c

890 g

d

445 g

answer is A.

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Detailed Solution

Moles of C57H110O6(s)=445890=0.5 moles 2C57H10O6(s)+163O2(g)→114CO2(g)+110H2O(l)nH2O=1104=552mH2O=552×18=495g
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