For the following reaction the mass of water produced from 445 g of C57H110O6 is:2C57H110O6s+163O2g→114CO2g+110H2O1

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490 g

442 g

495 g

890 g

answer is C.

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Detailed Solution

For the given reaction:2C57H110O6s+163O2g→114CO2g+110H2OIn=445890=0.5Now, moles of water =1102×0.5=27.5∴Mass of water =27.5×18=495 g

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