In the following reaction, MnO2+4HCl⟶MnCl2+2H2O+Cl22 moles of MnO2 react with 4 moles of HCl to form 11.2 LCl2 at STP. Thus, per cent yield of Cl2 is

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25%

50%

100%

75%

answer is B.

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Detailed Solution

MnO22 mol +44HCl4 mol⟶MnCl2+2H2O+Cl21But the yield is 11.2∴ Percentage yield =11.222.4×100=50%

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