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Q.

In the following sequence of reactions the maximum number of atoms present in molecule 'C' in one plane is_________.A→Cu tubeRed hot  B→anhydrous AlCl3CH3ClC(A is a lowest molecular weight alkyne)

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answer is 13.

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Detailed Solution

As A is a lowest molecular weight alkyne. So A is H - C ≡ C - H.Total 13 atom are present in same plane (7 carbon & 6 hydrogen atoms.)
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