Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations:$$A)$$ $$60$$ $$mLM10HCl+40$$ $$mLM10NaOH$$ $$B)$$ $$55$$ $$mLM10HCl+45$$ $$mLM10NaOHC)$$ $$75$$ $$mLM5HCl+25$$ $$mLM5NaOH$$ $$D)$$ $$100$$ $$mLM10HCl+100$$ $$mLM10NaOHpH$$ of which one of them will be equal to $$1$$?

Question

Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations:$$A)$$ $$60$$ $$mLM10HCl+40$$ $$mLM10NaOH$$               $$B)$$ $$55$$ $$mLM10HCl+45$$ $$mLM10NaOHC)$$ $$75$$ $$mLM5HCl+25$$ $$mLM5NaOH$$                $$D)$$ $$100$$ $$mLM10HCl+100$$ $$mLM10NaOHpH$$ of which one of them will be equal to $$1$$?

Infinity Learn · Accepted Answer

$$pH=1$$, so $$H+=10-1$$ For acid base mixture: $$N1V1-N2V2=N3V3$$  (For$$ NaOH and HCl ,Normality $$=$$ $$Molarity)  A. $$M1H+=60$$×$$110-40$$×$$110100=2$$×$$10-3M$$ i.e. $$pH=2.7$$ B. $$M2H+=55$$×$$110-45$$×$$110100=1100=10-2M$$ i.e. $$pH=2$$ C. $$M3H+=75$$×$$15-25$$×$$15100=10-1M$$ i.e. $$pH=1$$ D. $$M4H+=100$$×$$110-100$$×$$110200=0$$ i.e. $$pH=7$$

Q.

Unlock the Full Solution and Master the Concept