Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations:
$A) 60 mL \frac{M}{10} HCl + 40 mL \frac{M}{10} NaOH$ $B) 55 mL \frac{M}{10} HCl + 45 mL \frac{M}{10} NaOH$
$C) 75 mL \frac{M}{5} HCl + 25 mL \frac{M}{5} NaOH$ $D) 100 mL \frac{M}{10} HCl + 100 mL \frac{M}{10} NaOH$
pH of which one of them will be equal to 1?

Question

Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations:

$A) 60 mL \frac{M}{10} HCl + 40 mL \frac{M}{10} NaOH$ $B) 55 mL \frac{M}{10} HCl + 45 mL \frac{M}{10} NaOH$

$C) 75 mL \frac{M}{5} HCl + 25 mL \frac{M}{5} NaOH$ $D) 100 mL \frac{M}{10} HCl + 100 mL \frac{M}{10} NaOH$

pH of which one of them will be equal to 1?

Infinity Learn · Accepted Answer

$$pH=1$$, so $$H+=10-1$$ For acid base mixture: $$N1V1-N2V2=N3V3$$  (For$$ NaOH and HCl ,Normality $$=$$ $$Molarity)  A. $$M1H+=60$$×$$110-40$$×$$110100=2$$×$$10-3M$$ i.e. $$pH=2.7$$ B. $$M2H+=55$$×$$110-45$$×$$110100=1100=10-2M$$ i.e. $$pH=2$$ C. $$M3H+=75$$×$$15-25$$×$$15100=10-1M$$ i.e. $$pH=1$$ D. $$M4H+=100$$×$$110-100$$×$$110200=0$$ i.e. $$pH=7$$

Unlock the full solution & master the concept.

Ready to Test Your Skills?

free study material

Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations:A) 60 mLM10HCl+40 mLM10NaOH B) 55 mLM10HCl+45 mLM10NaOHC) 75 mLM5HCl+25 mLM5NaOH D) 100 mLM10HCl+100 mLM10NaOHpH of which one of them will be equal to 1?

Unlock the full solution & master the concept.

Ready to Test Your Skills?

free study material