Q.
Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations:A) 60 mLM10HCl+40 mLM10NaOH B) 55 mLM10HCl+45 mLM10NaOHC) 75 mLM5HCl+25 mLM5NaOH D) 100 mLM10HCl+100 mLM10NaOHpH of which one of them will be equal to 1?
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya
a
B
b
A
c
D
d
C
answer is D.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
pH=1, so H+=10-1 For acid base mixture: N1V1-N2V2=N3V3 (For NaOH and HCl ,Normality = Molarity) A. M1H+=60×110-40×110100=2×10-3M i.e. pH=2.7 B. M2H+=55×110-45×110100=1100=10-2M i.e. pH=2 C. M3H+=75×15-25×15100=10-1M i.e. pH=1 D. M4H+=100×110-100×110200=0 i.e. pH=7
Watch 3-min video & get full concept clarity