Q.
The formation of oxide ion O2− g, from oxygen atom requires first an exothermic and then an endothermic step as shown belowO(g)+e−→O−(g);ΔH⊖=−141kJmol−1O−(g)+e−→O−2(g);ΔH⊖=+780kmol−1Thus, process of formation of O2− in gas phase is unfavourable even though O2− is isoelectronic with neon. It is due to the fact that
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a
oxygen is more electronegative
b
addition of electron in oxygen results in larger size of the ion
c
electron repulsion outweighs the stability gained by achieving noble gas configuration
d
O¯ ion has comparatively smaller size than oxygen atom
answer is C.
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Detailed Solution
Although O2− has noble gas configuration and isoelectronic with neon but its formation is unfavourable due to the strong electronic repulsion between the negatively charged O¯ ion and the second electron being added.Hence, the electron repulsion outweighs the stability gained by achieving noble gas configuration.
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