The formation of the oxide ion Og2− requires first an exothermic and then an endothermic step as shown below Og + e− → Og2−; ΔH=−142 kJ mol−1Og + e → Og2−; ΔH=844 kJ mol−1This is because :
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a
O− ion has comparatively larger size than oxygen atom
b
Oxygen has high electron affinity
c
O− ion will tend to resist the addition of another electron
d
Oxygen is more electronegative
answer is C.
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Detailed Solution
O− acquires negative charge and thus shows repulsion for another electron.