In the formation of sulphur trioxide by the contact process, 2SO2+O2⇌2SO3, the rate of reaction was measured as d[O2]dt=3.0×10−4 mol L−1 s−1. The rate of reaction expressed in terms of SO3 will be

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3.0×10−4 mol L−1 s−1

6.0×10−4 mol L−1 s−1

1.5×10−4 mol L−1 s−1

4.5×10−4 mol L−1 s−1

answer is B.

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Detailed Solution

−d[O2]dt=+12d[SO3]dt3×10−4=12d[SO3]dtd[SO3]dt=6×10−4 M/sec

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