Four diatomic species are listed below. Identify the correct order in which the bond order is increasing in them

Bond order =Nb-Na2In NO, total electrons = 7 + 8 = 15∴ Configuration of NO=KK*,σ2s2,*σ2s2,σ2pz2,π2px2≈π2py2,*2px1∴  Bond order =8-32=52=2.5 In O2-,total electrons =16+1=17∴ Configuration of O2-=KK*,σ2s2,σ*2s2,σ2pz2π2px2=π2py2,π*2px2≈π*2py1∴  Bond order =8-52=32=1.5 In C22-, total electrons =12+2=14∴ Configuration of C22-=K*,σ2s2,σ*2s2,π2pz2≈π2py2 σ2pz2∴  Bond order =8-22=63=3In He2+,  total electrons = 4 -l = 3∴  Configuration of He2+=σls2,σ*ls1∴ Bond order =2-12=12=0.5Hence, correct order of bond order is He2+