First slide

PH of strong acids and strong bases

Question

Four grams of NaOH is dissolved in hundred litre solution. At 298 K, $p^{H}$ of the solution is

Easy

A

11
B

12.6990
C

11.3010
D

12

Solution

$N_{b} = [{OH}^{-}] = \frac{4}{40} \times \frac{1}{100} = 10^{- 3} N; p^{OH} = - \log 10^{- 3} = 3; p^{H} = 11;$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App