Four moles of electrons were transferred from anode to cathode in an experiment on electrolysis of water. The total volume of the two gases (dry and at STP) produced will be approximately (in litres)

During electrolysis of waterAt Cathode  4H+ + 4e- → 2H2At Anode     4OH- → 2H2O + O2 + 4e- 4 moles of electrons = 4 F electricity = 4eq of each gas is liberated.1 eq of H2 = 11.2 lit at STP4 eq of H2 = 4 x 11.2 lit = 44.8 lit1 eq of O2 = 5.6 lit at STP4 eq of O2 = 4 x 5.6 lit = 22.4 litTotal volume of both gases = 44.8 + 22.4 = 67.2 lit.