First slide

Theory of dilute solutions

Question

The freezing point of a solution prepared from 1.25 g of non-electrolyte and 20 g of water is 271.9 K. If the molar depression constant is 1.86 K mol^-1, then molar mass of the solute will be

Moderate

A

105.7
B

106.7
C

115.3
D

93.9

Solution

$∆ T_{f} = \frac{1000 K_{f} \times W_{2}}{M w_{2} \times W_{1}}, [∆ T = 273 - 271.9 = 1.1] 1.1 = \frac{1000 \times \times 1.86 \times 1.25}{M w_{2} \times 20} M w_{2} = 105.68$

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