The freezing point of a solution prepared from 1.25 g of non-electrolyte and 20 g of water is 271.9 K. If the molar depression constant is 1.86 K mol-1, then molar mass of the solute will be

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105.7

106.7

115.3

93.9

answer is A.

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Detailed Solution

∆Tf=1000Kf×W2Mw2×W1, ∆T=273-271.9=1.1 1.1=1000××1.86×1.25Mw2×20 Mw2=105.68

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