Q.
The freezing point of a solution prepared from 1.25 g of non-electrolyte and 20 g of water is 271.9 K. If the molar depression constant is 1.86 K mol-1, then molar mass of the solute will be
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a
105.7
b
106.7
c
115.3
d
93.9
answer is A.
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Detailed Solution
∆Tf=1000Kf×W2Mw2×W1, ∆T=273-271.9=1.1 1.1=1000××1.86×1.25Mw2×20 Mw2=105.68
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