For Freundlich adsorption isotherm, a plot of log (x/m) (y-axis) and log P (x-axis) gives a straight line. The intercept and slope for the line is 0.4771 and 2, respectively. The mass of gas, adsorbed per gram of adsorbent if the initial pressure is 0.04 atm is _________ × 10-4 g.(log 3 = 0.4771)
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
answer is 48.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
xm=k(P)1nlogxm=logk+1nlogP slope =1n=2,⇒n=12.Intercept logk=0.4771∴ K= Antilog (0.4771)=3 So, xm=k(P)1n=3×(0.04)2=48×10−4g