Q.
A fuel cell uses CH4(g) and forms CO32−at the anode. It is used to power a car with 80 amp, for 0.96 hr. How many litres of CH4(g) (stp.) would be required Vm=22.4 L/mol (F = 96500). Assume 100% efficiency.
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answer is 8.
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Detailed Solution
CH4+SO2→CO2−2+2H2Omol=i×tn×96500=80×0.96×60×608×96500=8.02
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