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Q.

A fuel cell uses CH4(g) and forms CO32−at the anode.  It is used to power a car with 80 amp, for 0.96 hr.  How many litres of CH4(g) (stp.) would be required Vm=22.4  L/mol              (F = 96500). Assume 100% efficiency.

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answer is 8.

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Detailed Solution

CH4+SO2→CO2−2+2H2Omol=i×tn×96500=80×0.96×60×608×96500=8.02
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