A fuel cell uses CH4g and forms CO32− at the anode. It is used to power a car with 80 Amp for 1 hour. How many liters of CH4g (at STP) would be required? Vm=22.7 L/mol&F=96500 Coulumbs . Assume 100% efficiency.

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8.05 L

8.47 L

4.18 L

4.04 L

answer is B.

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Detailed Solution

CH4+10 OH−→ CO32−+7 H2O+8 e−No. of Faradays required=18×80×3600×196500VCH4=18×80×3600×196500×22.7 L=8.47L

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