Q.

0.45 g of acid (mol. wt. = 90) was exactly neutralized by 20 ml of 0.5 (M) NaOH.The basicity of the given acid is

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a

1

b

2

c

3

d

4

answer is B.

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Detailed Solution

milliequivalents of acid = milliequivalents of base0.4590 × basicity = 20 × 0.5 × 10-3basicity = 90 ×20 × 0.5 × 10-30.45             = 2000 × 10-3 = 2
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0.45 g of acid (mol. wt. = 90) was exactly neutralized by 20 ml of 0.5 (M) NaOH.The basicity of the given acid is