0.84 g. of an acid of Molecular weight 225 is present in 100ml of the solution. 25ml of this solution required 28ml of N/10 NaOH solution for complete neutralisation. The basicity of the acid is

Acid                              NaOH(base)Va =25ml                        Vb = 28mlNa =?                             Nb = 0.1NAT equivalent point      VaNa = VbNb     25(Na) = 28(0.1)          Given , Wa = 0.84g  ,  GMW of acid =225g          Vsol = 100mlGEW of acid =75gGMW of acid = 225g