3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06 N) in a flask. After an hour it was filtered and the strength of the filtrate was found so be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is

Given, initial strength of acetic acid = 0.06 NFinal strength = 0.042N, volume given = 50 mL∴ Initial millimoles of CH3COOH=0.06×50=3 Final millimoles of CH3COOH=0.042×50=2.1∴ Millimoles of CH3COOH adsorbed =3-2.1=0.9mmol                                                            = 0.9x60 mg                                                            = 54 mg