$$3$$ g of activated charcoal was added to $$50$$ mL of acetic acid solution (0.06$$ $$N) in a flask. After an hour it was filtered and the strength of the filtrate was found so be $$0.042$$ N. The amount of acetic acid adsorbed (per$$ gram of $$charcoal) is

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Infinity Learn · Accepted Answer

Given, initial strength of acetic acid $$=$$ $$0.06$$ NFinal strength $$=$$ $$0.042N$$, volume given $$=$$ $$50$$ mL∴ Initial millimoles of $$CH3COOH=0.06$$×$$50=3$$ Final millimoles of $$CH3COOH=0.042$$×$$50=2.1$$∴ Millimoles of $$CH3COOH$$ adsorbed $$=3-2.1=0.9mmol$$                                                            $$=$$ $$0.9x60$$ mg                                                            $$=$$ $$54$$ mg

3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06 N) in a flask. After an hour it was filtered and the strength of the filtrate was found so be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is

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