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3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06 N) in a flask. After an hour it was filtered and the strength of the filtrate was found so be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is

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By Expert Faculty of Sri Chaitanya
a
18 mg
b
36 mg
c
42 mg
d
54 mg

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detailed solution

Correct option is D

Given, initial strength of acetic acid = 0.06 NFinal strength = 0.042N, volume given = 50 mL∴ Initial millimoles of CH3COOH=0.06×50=3 Final millimoles of CH3COOH=0.042×50=2.1∴ Millimoles of CH3COOH adsorbed =3-2.1=0.9mmol                                                            = 0.9x60 mg                                                            = 54 mg


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